Conditional Statements in C HackerRank Solution
Objective
if and else are two of the most frequently used conditionals in C/C++, and they enable you to execute zero or one conditional statement among many such dependent conditional statements. We use them in the following ways:
1. if: This executes the body of bracketed code starting with statement1 if condition evaluates to true.
if (condition) {
statement1;
...
}
2. if – else: This executes the body of bracketed code starting with statement1 if condition evaluates to true, or it executes the body of code starting with statement2 if condition evaluates to false. Note that only one of the bracketed code sections will ever be executed.
if (condition) {
statement1;
...
}
else {
statement2;
...
}
3. if – else if – else: In this structure, dependent statements are chained together and the condition for each statement is only checked if all prior conditions in the chain are evaluated to false. Once a condition evaluates to true, the bracketed code associated with that statement is executed and the program then skips to the end of the chain of statements and continues executing. If each condition in the chain evaluates to false, then the body of bracketed code in the else block at the end is executed.
if(first condition) {
...
}
else if(second condition) {
...
}
.
.
.
else if((n-1)'th condition) {
....
}
else {
...
}
Task
Given a positive integer denoting n, do the following:
-
If 1<=n<=9, print the lowercase English word corresponding to the number (e.g., one for 1, two for 2, etc.).
-
If n > 9, print Greater than 9.
Input Format
The first line contains a single integer, n.
Constraints
-
1<=n<=10^9
Output Format
If 1<=n<=9, then print the lowercase English word corresponding to the number (e.g., one for 1, two for 2, etc.); otherwise, print Greater than 9 instead.
Sample Input
5
Sample Output
five
Sample Input #01
8
Sample Output #01
eight
Sample Input #02
44
Sample Output #02
Greater than 9
Solution:
#include <assert.h>
#include <limits.h>
#include <math.h>
#include <stdbool.h>
#include <stddef.h>
#include <stdint.h>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
char* readline();
int main()
{
char* n_endptr;
char* n_str = readline();
int n = strtol(n_str, &n_endptr, 10);
if (n_endptr == n_str || *n_endptr != '\0') { exit(EXIT_FAILURE); }
// Write Your Code Here
if(n>=1 && n<=9)
{ if(n==1)
printf("one");
if(n==2)
printf("two");
if(n==3)
printf("three");
if(n==4)
printf("four");
if(n==5)
printf("five");
if(n==6)
printf("six");
if(n==7)
printf("seven");
if(n==8)
printf("eight");
if(n==9)
printf("nine");
}
else
printf("Greater than 9");
return 0;
}
char* readline() {
size_t alloc_length = 1024;
size_t data_length = 0;
char* data = malloc(alloc_length);
while (true) {
char* cursor = data + data_length;
char* line = fgets(cursor, alloc_length - data_length, stdin);
if (!line) { break; }
data_length += strlen(cursor);
if (data_length < alloc_length - 1 || data[data_length - 1] == '\n') { break; }
size_t new_length = alloc_length << 1;
data = realloc(data, new_length);
if (!data) { break; }
alloc_length = new_length;
}
if (data[data_length - 1] == '\n') {
data[data_length - 1] = '\0';
}
data = realloc(data, data_length);
return data;
}
Steps Used in solving the problem -
- We used if condition to check the number is in range 1 to 9.
- If the number is in range 1 to 9 then, we used switch statement to print the corresponding word for the input number.
- If the input is not between 1 and 9 inclusive, the program prints "Greater than 9"
