For Loop in C Solution
Objective
In this challenge, you will learn the usage of the for loop, which is a programming language statement which allows code to be executed until a terminal condition is met. They can even repeat forever if the terminal condition is never met.
The syntax for the for loop is:
for ( <expression_1> ; <expression_2> ; <expression_3> )
<statement>
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expression_1 is used for intializing variables which are generally used for controlling the terminating flag for the loop.
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expression_2 is used to check for the terminating condition. If this evaluates to false, then the loop is terminated.
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expression_3 is generally used to update the flags/variables.
The following loop initializes i to 0, tests that i is less than 10, and increments i at every iteration. It will execute 10 times.
for(int i = 0; i < 10; i++) {
...
}
Task
For each integer n in the interval [a,b] (given as input) :
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If 1<=n<=9, then print the English representation of it in lowercase. That is “one” for 1, “two” for 2, and so on.
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Else if n>9 and it is an even number, then print “even”.
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Else if n>9 and it is an odd number, then print “odd”.
Input Format
The first line contains an integer, a.
The seond line contains an integer, b.
Constraints
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1<=a<=b<=10^6
Output Format
Print the appropriate English representation,even, or odd, based on the conditions described in the ‘task’ section.
Note: [a,b] = {x ∈ Z | a <= x <= b} = {a, a+1,....,b}
Sample Input
8
11
Sample Output
eight
nine
even
odd
Solution:
#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>
int main() {
int a, b;
scanf("%d\n%d", &a, &b);
for (int i = a; i <= b; i++) {
if (i == 1) {
printf("one\n");
} else if (i == 2) {
printf("two\n");
} else if (i == 3) {
printf("three\n");
} else if (i == 4) {
printf("four\n");
} else if (i == 5) {
printf("five\n");
} else if (i == 6) {
printf("six\n");
} else if (i == 7) {
printf("seven\n");
} else if (i == 8) {
printf("eight\n");
} else if (i == 9) {
printf("nine\n");
} else if (i % 2 == 0) {
printf("even\n");
} else {
printf("odd\n");
}
}
return 0;
}
Steps Used in solving the problem -
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Step 1: First, we imported the required libraries.
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Step 2: Then, we declared the main function. Inside our function, we declared two integer variables. We have also used the scanf function to take inputs for our declared variables.
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Step 3: Then, we created a For loop that iterates from the value of variable "a" to the value of variable "b" (inclusive)
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Step 4: Then, we used a switch statement to print the corresponding word for the input number. This will also check if the number is even or odd.
