Check Leap Year Hackerrank Solution

We all are tought in our school that each year has 365 days. But once in a four year we have a month of february with 29 days. So every four year we have 366 days in the year. That particular is know as a leap year.

What is a leap year?

We all are taught in our school that each year has 365 days. But once in a four year we have a month of february with 29 days. So every four year we have 366 days in the year. That particular is know as a leap year.

How  to solve leap year problem using Python?

1. To solve this problem you should understand that a leap year occurs in every 4 years. That means that for sure the leap year is perfectly divisible by 4.
2. Also for the century years like 1900, 2000, 2100, 1800 leap year occurs consecutively. Which means that if 2000 is a leap year, than the next century year 2100 wont be a leap year. 
3. Which means that we need to create two conditions one to check if the number or year is a century year and one to check if the number is a normal year. This could be done by checking that the number is divisible by 100 as well as 400. This condition makes a century year a leap year.

def is_leap(year):
    leap = False
    
    # Write your logic here
    if year%4 == 0:            #Here we are checking if the year is normal year
        leap = True
        if year%100 == 0:        #Here we are checking if the year is a century year      
            if year%400 == 0:
                leap = True
            else:
                leap = False
        
                
    

                
    

    return leap

year = int(input())
print(is_leap(year))