Python If-Else HackerRank Solution
Python If-Else HackerRank Solution
In this tutorial, we will solve the HackerRank If-else problem in Python.
Task
Given an integer,n, perform the following conditional actions:
- If n is odd, print Weird
- If n is even and in the inclusive range of 2 to 5, print Not Weird
- If n is even and in the inclusive range of 6 to 20, print Weird
- If n is even and greater than 20, print Not Weird
Input Format
A single line containing a positive integer, n.
Constraints
- 1 ≤ n ≤ 100
Output Format
Print Weird if the number is weird. Otherwise, print Not Weird
Sample Input 0
|
3 |
Sample Output 0
|
Weird |
Explanation 0
n = 3
n is odd and odd numbers are weird, so print Weird.
Sample Input 1
|
24 |
Sample Output 1
|
Not Weird |
Explanation 1
n = 24
n > 20 and n is even, so it is not weird.
Solution: Method 1
if __name__ == '__main__':
n = int(input().strip())
if n%2 != 0:
print("Weird")
elif n%2 == 0 and n>2 and n<=5:
print("Not Weird")
elif n%2 ==0 and n > 6 and n <=20:
print("Weird")
else:
print("Not Weird")
Steps Used in solving the problem -
Step 1: first n will take int type input.
Step 2: then we had given an if condition i.e if n%2 is not equal to zero (odd number) then the compiler will print “Weird”.
Step 3: the second condition is if n%2 is equal to zero (even number) and n is greater than 2 and less than equals 5 then the compiler will print “Weird”.
Step 4: Similarly, if n%2 is equal to zero (even number) and n is greater than 6 and less than equals 20 then the compiler will print “Weird”.
Step 5: if the integer doesn't follow any of these conditions then the compiler will print "Not Weird".
Solution: Method 2
if __name__ == '__main__':
n = int(input().strip())
if n%2 != 0:
print("Weird")
elif n in range(2,5) and n%2==0:
print("Not Weird")
elif n in range(6,21) and n%2==0:
print("Weird")
else:
print("Not Weird")
Steps Used in solving the problem -
Step 1: first n will take int type input.
Step 2: then we had given an if condition i.e if n%2 is not equal to zero (odd number) then the compiler will print “Weird”.
Step 3: the second condition is if n is in the range (2,5) and n%2 is equal to zero(even number) then the compiler will print “Weird”.
Step 4: Similarly, if n is in the range (6,21) and n%2 is equal to zero (even number) then the compiler will print “Weird”.
(Note - I have given a range from 6 to 21 so, the compiler will take 20 also)
Step 5: if the integer doesn't follow any of these conditions then the compiler will print "Not Weird".
