ABC is a right triangle, 90o at B.
Therefore, angle ABC = 90o.
Point M is the midpoint of hypotenuse AC.
You are given the lengths AB and BC.
Your task is to find angle MBC(angle theta, as shown in figure) in degrees.
The first line contains the length of side AB.
The second line contains the length of side BC.
0 < AB <= 100
0 < BC <= 100
Lengths AB and BC are natural numbers.
Output angle MBC in degrees.
Note: Round the angle to the nearest integer.
If angle is 56.5000001°, then output 57°.
If angle is 56.5000000°, then output 57°.
If angle is 56.4999999°, then output 56°.
10
10
45°
from math import degrees, atan2
AB = float(input())
BC = float(input())
MBC = round(degrees(atan2(AB, BC)))
print((str(MBC)), chr(176), sep='')
Step 1: First we imported degrees and atan2 from math.
Step 2: then we have taken the input of AB and BC.
Step 3: After this, we used the atan2 function to calculate the angle MBC. we have used the round method to change our ans in round number.
Step 4: At last we have returned our ans as a string. Here, we have used char(176) to add the degree symbol.
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