Python Text Alignment HackerRank Solution
In Python, a string of text can be aligned left, right and center.
.ljust(width)
This method returns a left aligned string of length width.
>>> width = 20
>>> print 'HackerRank'.ljust(width,'-')
HackerRank----------
.center(width)
This method returns a centered string of length width.
>>> width = 20
>>> print 'HackerRank'.center(width,'-')
-----HackerRank-----
.rjust(width)
This method returns a right aligned string of length width.
>>> width = 20
>>> print 'HackerRank'.rjust(width,'-')
----------HackerRank
Task
You are given a partial code that is used for generating the HackerRank Logo of variable thickness. Your task is to replace the blank (______) with rjust, ljust or center.
Input Format
A single line containing the thickness value for the logo.
Constraints
0 < thickness < 50
Output Format
Output the desired logo.
Sample Input
5
Sample Output 0
H
HHH
HHHHH
HHHHHHH
HHHHHHHHH
HHHHH HHHHH
HHHHH HHHHH
HHHHH HHHHH
HHHHH HHHHH
HHHHH HHHHH
HHHHH HHHHH
HHHHHHHHHHHHHHHHHHHHHHHHH
HHHHHHHHHHHHHHHHHHHHHHHHH
HHHHHHHHHHHHHHHHHHHHHHHHH
HHHHH HHHHH
HHHHH HHHHH
HHHHH HHHHH
HHHHH HHHHH
HHHHH HHHHH
HHHHH HHHHH
HHHHHHHHH
HHHHHHH
HHHHH
HHH
H
Solution:
thickness = int(input()) #This must be an odd number
c = 'H'
for i in range(thickness):
print((c*i).rjust(thickness-1)+c+(c*i).ljust(thickness-1))
for i in range(thickness+1): print((c*thickness).center(thickness*2)+(c*thickness).center(thickness*6))
for i in range((thickness+1)//2):
print((c*thickness*5).center(thickness*6))
for i in range(thickness+1): print((c*thickness).center(thickness*2)+(c*thickness).center(thickness*6))
for i in range(thickness): print(((c*(thickness-i-1)).rjust(thickness)+c+(c*(thickness-i-1)).ljust(thickness)).rjust(thickness*6))
Steps Used in solving the problem -
Step 1: First we created a variable to take input.
Step 2: then, we created a string H.
Step 3: then, we created a first for loop to print the top cone, a second loop to print top pillars, a third loop to print middle belt, fourth for loop to print bottom pillars, and fifth for loop to print the bottom cone.
