In this tutorial, we are going to solve a leetcode problem, Group Anagrams in python.
Task:
Given an array of strings strs, group the anagrams together. You can return the answer in any order.
An Anagram is a word or phrase formed by rearranging the letters of a different word or phrase, typically using all the original letters exactly once.
Input: strs = ["eat","tea","tan","ate","nat","bat"]
Output: [["bat"],["nat","tan"],["ate","eat","tea"]]
Input: strs = [""]
Output: [[""]]
Input: strs = ["a"]
Output: [["a"]]
class Solution:
def groupAnagrams(self, strs: List[str]) -> List[List[str]]:
if len(strs) == 0:
return [strs]
elif len(strs) == 1:
return [strs]
dct = {}
for i in range(len(strs)):
sorted_ = "".join(sorted(strs[i]))
if sorted_ not in dct.keys():
dct[sorted_] = [strs[i]]
else:
dct[sorted_].append(strs[i])
return dct.values()
step1: First we added the base case for the problem.
step2: then, we initiated an empty dictionary and looped through the strs.
step3: then, we created a string sorted_ which join the sorted strs[i].
step4: Now, we add the sorted_ string into the dictionary as key and strs[i] as its value.
step5; then we return the values of dct as our final answer.
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