Python programme to find the number of indices from the string Codechef solution
Problem:
Chef has a string S of length N. He needs to find the number of indices i (1iN1) such that the i-th character of this string is a consonant and the i+1-th character is a vowel. However, he is busy, so he asks for your help.
Note: The letters 'a', 'e', 'i', 'o', and u' are vowels; all other lowercase English letters are consonants.
Input
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The first line of the input contains a single integer, T, denoting the number of test cases. The description of T-test cases follows.
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The first line of each test case contains a single integer, N.
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The second line contains a single string S with length N.
Output
For each test case, print a single line containing one integer: the number of occurrences of a vowel immediately after a consonant.
Constraints
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1<=T<=100
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1<=N<=10
Sample Input:
3
6
bazeci
3
abu
1
0
Sample Output:
3
1
0
Explanation:
Example case 1: The vowel 'a' follows after the consonant 'b', 'e' follows after 'z, and 'i' follows after 'c', so the answer is 3.
Example case 2: The only vowel 'u' follows after 'b', so the answer is 1.
Solution
t=int(input(“Enter the number of terms: “))
for i in range(t):
c=0
x=int(input(“Enter a number: “))
s=input(“Enter a string: “)
m=['a','e','i','o','u']
for j in range(1,len(s)):
if s[j] in m and s[j-1] not in m:
c+=1
print(c)
Steps to solve this problem:
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Ask the user to enter the number of terms to execute the loop and store it in
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Initialise a variable with 0.
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Ask the user to enter a number.
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Ask the user to enter a string.
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Make a list of vowels and assign them to
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In the loop, Check if string characters are present in vowels. If present, increase the value of c by 1.
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Print the value of c
