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Check if a Given Number is Perfect

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A Python program to check if a given number is a perfect number by summing its proper divisors.

Code Explanation in Points:

Function Definition:
- is_perfect(n) checks if a number n is a perfect number.
Initialize Sum of Divisors:
- sum_div = 0 → Stores the sum of all divisors of n.
Loop to Find Divisors:
- Iterate i from 1 to n-1.
- If n % i == 0, add i to sum_div.
Compare Sum with n:
- If sum_div == n → n is a Perfect Number (returns True).
- Else → n is Not a Perfect Number (returns False).
User Input and Function Call:
- Take input (num) from the user.
- Call is_perfect(num) and print the result.

Program:

def is_perfect(n):

    sum_div = 0  

    for i in range(1, n):  

        if n % i == 0:  

            sum_div += i  



    return sum_div == n  



num = int(input("Enter a number: "))  



if is_perfect(num):  

    print(num, "is a Perfect Number")  

else:  

    print(num, "is NOT a Perfect Number")

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Check if a Given Number is Perfect

Code Explanation in Points:

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