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Python program to check whether an integer is armstrong number or not

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A Python program to check whether a given integer is an Armstrong number or not.

Here’s a point-wise explanation of the code:

Input: The program prompts the user to input a number (num).
Convert to String: The number is converted to a string to easily access each digit.
Calculate Power: The power is determined by the length of the string, which represents the number of digits in the number.
Sum Digits Raised to Power: The program iterates through each digit, raises it to the power of the total number of digits, and adds the result to total.
Comparison: The program checks if the sum (total) is equal to the original number. If true, it’s an Armstrong number; otherwise, it's not.
Output: It prints whether the number is an Armstrong number or not.

For example:

Input: 153
Output: 153 is an Armstrong number, because 1^3 + 5^3 + 3^3= 153.

Program:

def is_armstrong_number_checker(number):

    convert_string=str(number)

    power=len(convert_string)

    total=0

    for i in convert_string:

        total+= int(i)**power

    return number== total

num=int(input("enter a number:"))  

if is_armstrong_number_checker(num):

    print(f"{num} is armstrong number")

else:

    print(f"{num} is not armstrong number")

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Python program to check whether an integer is armstrong number or not

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